What happens when break leaves a for...of loop before its generator finishes?

What happens when break leaves a for...of loop before its generator finishes?

1. The loop calls the iterator return method, allowing a surrounding finally block to run.
2. The loop waits for garbage collection to run the generator finally block.
3. The generator restarts and consumes its remaining values in the background.
4. The loop converts every remaining value into an array before exiting.