Why does constructing T from std::move(const_value) commonly call T(const T&) instead of …

Why does constructing T from std::move(const_value) commonly call T(const T&) instead of T(T&&)?

1. std::move preserves const, and T&& cannot bind to const T&&.
2. std::move always copies class objects.
3. Move construction is disabled whenever a copy constructor exists.